document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464763>Question 464763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the complemnt of an angle is one third of its supplement.find the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318434 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the complemnt of an angle is one third of its supplement.find the angles\r<BR>\n" );
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document.write( "Let x = the angle<BR>\n" );
document.write( " 9o-x = the complement of the angle<BR>\n" );
document.write( "180-x = the supplement of the angle\r<BR>\n" );
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document.write( "90-x = (180-x)/3<BR>\n" );
document.write( "3(90-x) = 180-x<BR>\n" );
document.write( "270 - 3x = 180 -x<BR>\n" );
document.write( "270 - 180 = 3x - x<BR>\n" );
document.write( "2x = 90<BR>\n" );
document.write( "x = 45\r<BR>\n" );
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document.write( "The angle is 45.<BR>\n" );
document.write( "The complement is 45 (90-45).<BR>\n" );
document.write( "The supplement is 135 (180-45). </SPAN>\n" );
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