document.write( "Question 464769: The perimeter of a rectangle is 34cm, and the diagonal is 13cm. Determine the lengths of the sides of the rectangle. \r
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document.write( "I need to set this up in a quadratic equation then solve. I have several problems like this and knowing how to set them up would be a big help. Thanks. \n" );
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Algebra.Com's Answer #318420 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is 34cm, and the diagonal is 13cm. Determine the lengths of the sides of the rectangle. \n" ); document.write( "... \n" ); document.write( "let x=length of rectangle \n" ); document.write( "let y=width of rectangle \n" ); document.write( ".. \n" ); document.write( "2x+2y=perimeter=34 \n" ); document.write( "divide by 2 \n" ); document.write( "x+y=17 \n" ); document.write( ".. \n" ); document.write( "x^2+y^2=13^2=169 (Pythagorean Theorem) \n" ); document.write( "y^2=169-x^2 \n" ); document.write( "y=ħsqrt(169-x^2) \n" ); document.write( "since y>0, use the positive sqrt \n" ); document.write( "x+y=17 \n" ); document.write( "x+sqrt(169-x^2)=17 \n" ); document.write( "sqrt(169-x^2)=17-x \n" ); document.write( "square both sides \n" ); document.write( "169-x^2=289-34x+x^2 \n" ); document.write( "2x^2-34x+120=0 \n" ); document.write( "x^2-17x+60=0 \n" ); document.write( "(x-5)(x-12)=0 \n" ); document.write( "x=5 \n" ); document.write( "y=17-x=12 \n" ); document.write( "or \n" ); document.write( "x=12 \n" ); document.write( "y=17-x=5 \n" ); document.write( ".. \n" ); document.write( "ans: \n" ); document.write( "length of rectangle=5 \n" ); document.write( "Width of rectangle=12 \n" ); document.write( "or \n" ); document.write( "length of rectangle=12 \n" ); document.write( "Width of rectangle=5 \n" ); document.write( " |