document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464766>Question 464766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor completely\r<BR>\n" );
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document.write( "(5a-3)^2 -6(5a-3)+9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318412 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can let y = 5a-3 and we get a simpler-looking quadratic:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (5a-3)^2 - 6(5a-3) + 9 = y^2 - 6y + 9\">\r<BR>\n" );
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document.write( "The quadratic factors:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE y^2 - 6y + 9 = (y-3)(y-3)\">\r<BR>\n" );
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document.write( "We want to express in terms of a, not y, so we substitute:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE ((5a-3)-3)((5a-3)-3) = (5a-6)(5a-6)\"> </SPAN>\n" );
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