document.write( "Question 48121This question is from textbook Algebra 2
\n" ); document.write( ": This is a Value Word Problems lesson. I learned it in chapter 19 but it doesn't help for my problem. Here it is
\n" ); document.write( "The expensive ones cost $7 each, whereas the worthless ones sold for only $2 each. Monongahela spent $111 and bought three more expensive ones than worthless ones. How may of each kind did she buy.
\n" ); document.write( "THE ANSWER IS 10 WORTHLESS ONES AND 13 EXPENSIVE ONES. I WANT TO KNOW HOW DID THEY GET THAT. \r
\n" ); document.write( "\n" ); document.write( "PLEASE AND THANK YOU
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Algebra.Com's Answer #31841 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
You are working with two different variables, x is one variable and y is the other variable. Since you have two variables, use the following formula:
\n" ); document.write( "Ax + By = C
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\n" ); document.write( "A = rate, cost or percent of A = $7
\n" ); document.write( "x = the amount or number of A = x
\n" ); document.write( "B = rate, cost or percent of B = $2
\n" ); document.write( "y = the amount or number of B = y
\n" ); document.write( "C = the total amount = $111
\n" ); document.write( ".
\n" ); document.write( "Expensive DISABLED_event_ones= $7x [We do not know how many expensive items are available]
\n" ); document.write( "Worthless DISABLED_event_ones= $2y [We do not know how many worthless items are available]
\n" ); document.write( "Total amount spent = C = $111
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\n" ); document.write( "Ax + By = C [Formula for linear equations]
\n" ); document.write( "7x + 2y = 111 [Plug-in the values]
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\n" ); document.write( "But, there is one more piece of information -- \"...and bought three more expensive ones than worthless ones\".
\n" ); document.write( "This translate into:
\n" ); document.write( "Number of expensive ones (x) = Number of Worthless ones (y) + 3 more
\n" ); document.write( "x = y + 3 [Substitute this (y + 3) in the equation]
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\n" ); document.write( "7(y+3) + 2y = 111 [Simplify]
\n" ); document.write( "7y + 21 + 2y = 111 [Solve for y]
\n" ); document.write( "9y + 21 = 111
\n" ); document.write( "9y + 21 - 21 = 111 - 21
\n" ); document.write( "9y = 90
\n" ); document.write( "9y/9 = 90/9
\n" ); document.write( "y = 10
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\n" ); document.write( "Plug (y=10) back into the original equation and solve for x]
\n" ); document.write( "7x + 2y = 111
\n" ); document.write( "7x + 2(10) = 111
\n" ); document.write( "7x + 20 = 111
\n" ); document.write( "7x + 20 - 20 = 11 - 20
\n" ); document.write( "7x = 91
\n" ); document.write( "7x/7 = 91/7
\n" ); document.write( "x = 13
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\n" ); document.write( "Check by plugging all of the values back into the original equation.
\n" ); document.write( "7x + 2y = 111
\n" ); document.write( "7(13) + 2(10) = 111
\n" ); document.write( "7(13) + 2(10) = 111
\n" ); document.write( "111 = 111 [Checks out]\r
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