document.write( "Question 48121This question is from textbook Algebra 2
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document.write( ": This is a Value Word Problems lesson. I learned it in chapter 19 but it doesn't help for my problem. Here it is
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document.write( "The expensive ones cost $7 each, whereas the worthless ones sold for only $2 each. Monongahela spent $111 and bought three more expensive ones than worthless ones. How may of each kind did she buy.
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document.write( "THE ANSWER IS 10 WORTHLESS ONES AND 13 EXPENSIVE ONES. I WANT TO KNOW HOW DID THEY GET THAT. \r
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document.write( "PLEASE AND THANK YOU \n" );
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Algebra.Com's Answer #31841 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! You are working with two different variables, x is one variable and y is the other variable. Since you have two variables, use the following formula: \n" ); document.write( "Ax + By = C \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "A = rate, cost or percent of A = $7 \n" ); document.write( "x = the amount or number of A = x \n" ); document.write( "B = rate, cost or percent of B = $2 \n" ); document.write( "y = the amount or number of B = y \n" ); document.write( "C = the total amount = $111 \n" ); document.write( ". \n" ); document.write( "Expensive DISABLED_event_ones= $7x [We do not know how many expensive items are available] \n" ); document.write( "Worthless DISABLED_event_ones= $2y [We do not know how many worthless items are available] \n" ); document.write( "Total amount spent = C = $111 \n" ); document.write( ". \n" ); document.write( "Ax + By = C [Formula for linear equations] \n" ); document.write( "7x + 2y = 111 [Plug-in the values] \n" ); document.write( ". \n" ); document.write( "But, there is one more piece of information -- \"...and bought three more expensive ones than worthless ones\". \n" ); document.write( "This translate into: \n" ); document.write( "Number of expensive ones (x) = Number of Worthless ones (y) + 3 more \n" ); document.write( "x = y + 3 [Substitute this (y + 3) in the equation] \n" ); document.write( ". \n" ); document.write( "7(y+3) + 2y = 111 [Simplify] \n" ); document.write( "7y + 21 + 2y = 111 [Solve for y] \n" ); document.write( "9y + 21 = 111 \n" ); document.write( "9y + 21 - 21 = 111 - 21 \n" ); document.write( "9y = 90 \n" ); document.write( "9y/9 = 90/9 \n" ); document.write( "y = 10 \n" ); document.write( ". \n" ); document.write( "Plug (y=10) back into the original equation and solve for x] \n" ); document.write( "7x + 2y = 111 \n" ); document.write( "7x + 2(10) = 111 \n" ); document.write( "7x + 20 = 111 \n" ); document.write( "7x + 20 - 20 = 11 - 20 \n" ); document.write( "7x = 91 \n" ); document.write( "7x/7 = 91/7 \n" ); document.write( "x = 13 \n" ); document.write( ". \n" ); document.write( "Check by plugging all of the values back into the original equation. \n" ); document.write( "7x + 2y = 111 \n" ); document.write( "7(13) + 2(10) = 111 \n" ); document.write( "7(13) + 2(10) = 111 \n" ); document.write( "111 = 111 [Checks out]\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |