document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464757>Question 464757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose K=2^5*7*11, L=2^3*7*11*13, M=2*29^2, and N=4*11*13^2*29. Which is the least common multiple of each of the following (in factored form.)\r<BR>\n" );
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document.write( "A. K and L<BR>\n" );
document.write( "B. M and N<BR>\n" );
document.write( "C. K and M<BR>\n" );
document.write( "D. K, L, and N </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318408 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A: If we arrange the factors side by side:\r<BR>\n" );
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document.write( "22222 7 11<BR>\n" );
document.write( "222 7 11 13\r<BR>\n" );
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document.write( "The highest number of 2's is 5, the highest number of 7's, 11's and 13's are 1 each. The LCM of K and L is therefore 2^5*7*11*13.\r<BR>\n" );
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document.write( "Try the others the same way. Another way to find the LCM is to think of it as taking the union of two sets; if we visualize K = {2,2,2,2,2,7,11} and L = {2,2,2,7,11,13} then the LCM is the union of the two sets, or {2,2,2,2,2,7,11,13} (elements in either K or L). It's not exactly the same as taking the union of the sets since the 2's are assumed to be distinct, but this method will work. </SPAN>\n" );
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