document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464744>Question 464744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the digit in the tens place of a two digit number is three times that in the units place.if the digits are reversed the new number will be 36 less than the original number. find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318403 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the ten's digit be x<BR>\n" );
document.write( "units digit be y\r<BR>\n" );
document.write( "\n" );
document.write( "x=3y<BR>\n" );
document.write( "x-3y=0.....................1<BR>\n" );
document.write( "10y+x=10x+y+36<BR>\n" );
document.write( "9y-9x=36<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "y-x=4......................2\r<BR>\n" );
document.write( "\n" );
document.write( "add (1) & (2)<BR>\n" );
document.write( "-2y=4<BR>\n" );
document.write( "y=-2<BR>\n" );
document.write( "x=3y<BR>\n" );
document.write( "x=-6<BR>\n" );
document.write( "The number is -62 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );