document.write( "Question 424443: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced? \n" ); document.write( "
Algebra.Com's Answer #318391 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 90% sulfuric acid=10% water \n" ); document.write( ".90m+5(1.00)=.5(m+5) \n" ); document.write( ".90m+5=.5m+2.5 \n" ); document.write( ".4m=2.5 \n" ); document.write( "m=2.5/.4=6.25 \n" ); document.write( "You started with 6.25 liters of 90% solution. Add the 5 liters of distilled water, and you have 11.25 liters of a 50% solution.. \n" ); document.write( " |