document.write( "Question 424443: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced? \n" ); document.write( "
Algebra.Com's Answer #318391 by jorel1380(3719)\"\" \"About 
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90% sulfuric acid=10% water
\n" ); document.write( ".90m+5(1.00)=.5(m+5)
\n" ); document.write( ".90m+5=.5m+2.5
\n" ); document.write( ".4m=2.5
\n" ); document.write( "m=2.5/.4=6.25
\n" ); document.write( "You started with 6.25 liters of 90% solution. Add the 5 liters of distilled water, and you have 11.25 liters of a 50% solution..
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