document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424536>Question 424536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs to produce a 40% acid mixture. She has 25% strength solution and 80% strength solution on hand. <BR>\n" );
document.write( "Rouding to the nearest thousandth (3 decimal places; nearest mL), how much 25% solution does she add to create 1 liter of the 40% strength mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318388 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 litre x .4=.4<BR>\n" );
document.write( "m+n=1<BR>\n" );
document.write( ".25m+.8n=.4<BR>\n" );
document.write( "25m+80n=40<BR>\n" );
document.write( "25m+25n=25<BR>\n" );
document.write( "55n=15<BR>\n" );
document.write( "n=15/55=3/11<BR>\n" );
document.write( "m=8/11<BR>\n" );
document.write( "The chemist need 8/11ths liter of 25% solution and 3/11ths liter of 80% solution for his mix.. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );