document.write( "Question 464620: If the difference of two numbers is 49. The larger number is 3 less than 5 times the smaller number. Choose the answer with the correct system of equations used to solve this problem. \r
\n" ); document.write( "\n" ); document.write( "a. 5x - 3 = 49 and y - x = 5 \r
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\n" ); document.write( "\n" ); document.write( "c. y - x = 3 and 5x + y = 49 \r
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Algebra.Com's Answer #318304 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x = the larger number\r\n" );
document.write( "Let y = the smaller number\r\n" );
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document.write( ">>...the difference of two numbers is 49...<\r\n" );
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document.write( "That says the same as\r\n" );
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document.write( "    The larger minus the smaller equals 49, or\r\n" );
document.write( "             x   -         y        =   49            \r\n" );
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document.write( "So the first equation is x - y = 49\r\n" );
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document.write( ">>...The larger number is 3 less than 5 times the smaller number...<<\r\n" );
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document.write( "Replace \"the larger number\" by x and \"the smaller number\" by y\r\n" );
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document.write( ">>...x is 3 less than 5 times y...<<\r\n" );
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document.write( "Replace \"is\" by \"=\" and \"5 times y\" by \"5y\"\r\n" );
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document.write( ">>...x = 3 less than 5y...<<\r\n" );
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document.write( "That means to make 5y less by subtracting 3 from it:\r\n" );
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document.write( ">>...x = 5y - 3...<<\r\n" );
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document.write( "So the answer is b.\r\n" );
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document.write( "Edwin

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