document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464577>Question 464577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The greater of two numbers is 3 more than the smaller. If twice the smaller is added to the greater, the result is 30. Find the numbers. I got this far:\r<BR>\n" );
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document.write( "x = number<BR>\n" );
document.write( "Lg.# = (x+3)+2x<BR>\n" );
document.write( "Sm.# = x<BR>\n" );
document.write( "Result = 30\r<BR>\n" );
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document.write( "My setup is wrong I know because I can't get the two numbers that add to 30. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318272 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "numbers are x and x+3\r<BR>\n" );
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document.write( "according to question, 2x + (x+3) = 30\r<BR>\n" );
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document.write( "=> 3x = 27\r<BR>\n" );
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document.write( "=> x= 9\r<BR>\n" );
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document.write( "numbers are 9 and 12.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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