document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464568>Question 464568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simplifying the fractions (I have always struggled with fractions). Is the answer I gave enough or do I need to go further, and if so, please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318265 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "ans: \r<BR>\n" );
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document.write( "165*(a/b)^3*(b/a)^8 \r<BR>\n" );
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document.write( "= 165*(b/a)^5\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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