document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464487>Question 464487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle exceeds its breadth by 7cm.if the length is decreased by 4 cm and the breadth is increased by 3 cm.the area of the new rectangle is the area of the original rectangle.find the length and the breadth of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318220 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the breadth of the rectangle<BR>\n" );
document.write( "x+ 7 = the length of the rectangle \r<BR>\n" );
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document.write( "(x+7-4)(x+3) = x(x+7)<BR>\n" );
document.write( "x^2+6x+9 = x^2+7x<BR>\n" );
document.write( "9=7x-6x<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "x+7 = 16\r<BR>\n" );
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document.write( "The length of the rectangle is 16 cm.<BR>\n" );
document.write( "The breadth of the rectangle is 9 cm. </SPAN>\n" );
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