document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464489>Question 464489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 150 into three parts such that the second number is five-sixths the first and the third number is four-fifths the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318219 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the first number <BR>\n" );
document.write( "  5x/6= the second number<BR>\n" );
document.write( "(4/5)(5x/6) = the third number= 2x/3\r<BR>\n" );
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document.write( "x+5x/6+2x/3 = 150<BR>\n" );
document.write( "Multiply both sides by 6 to get<BR>\n" );
document.write( "6x+5x+4x = 900<BR>\n" );
document.write( "x = 900/15<BR>\n" );
document.write( "x = 60 (first number)<BR>\n" );
document.write( "2nd number:<BR>\n" );
document.write( "5*60/6 = 50<BR>\n" );
document.write( "3rd number:<BR>\n" );
document.write( "4*50/5 = 40\r<BR>\n" );
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document.write( "The numbers are 60, 50, and 40. </SPAN>\n" );
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