document.write( "Question 463912: I would sincerely appreciate it if you could please help me solve this grade 11 math equation: 23/(x-1) + 3 - 70/(x^2-4x+3) = 0
\n" ); document.write( "I know that when (x^2-4x+3) is factored, it becomes (x-1)(x-3), and that I need to get rid of the denominator to solve the question, but I'm experiencing some difficulty finishing the question. \n" ); document.write( "
Algebra.Com's Answer #318216 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
23/(x-1) + 3 - 70/(x^2-4x+3) = 0
\n" ); document.write( "...
\n" ); document.write( "23/(x-1) + 3 - 70/(x^2-4x+3) = 0
\n" ); document.write( "23/(x-1) + 3 - 70/(x-1)(x-3) = 0
\n" ); document.write( "LCD:(x-1)(x-3)
\n" ); document.write( "multiply each term by the LCD, getting rid of the fractions.
\n" ); document.write( "23(x-3)+3(x-1)(x-3)-70=0
\n" ); document.write( "23(x-3)+3(x^2-4x+3)-70=0
\n" ); document.write( "23x-69+3x^2-12x+9-70=0
\n" ); document.write( "3x^2+11x-130=0
\n" ); document.write( "solve by following quadratic formula:
\n" ); document.write( "..
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "..
\n" ); document.write( "a=3, b=11, c=-130
\n" ); document.write( "x=[-11ħsqrt(11^2-4*3*-130)]/2*3
\n" ); document.write( "x=[-11ħsqrt(121+1560)]6
\n" ); document.write( "x=[-11ħ√1681]/6
\n" ); document.write( "x=[-11ħ41]/6
\n" ); document.write( "x=30/6=5
\n" ); document.write( "or
\n" ); document.write( "x=52/6\r
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