document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464461>Question 464461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three consecutive numbers whose sum is equal to their products.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318203 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3,-2,-1 works as well. But then {-1,0,1}, {1,2,3} and {-3,-2,-1} are the only sets of three consecutive integers satisfying this property, because if we were to write it algebraically (e.g. (a-1) + a + (a+1) = (a-1)a(a+1), 3a = a(a-1)(a+1)) we would get a cubic, which has at most three distinct solutions for a. </SPAN>\n" );
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