document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464422>Question 464422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show me the steps to solve 5 over 3x + 3 over x = 1? Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318180 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/3x + 3/x = 1<BR>\n" );
document.write( "3x[5/3x + 3/x = 1] {multiplied entire equation by least common denominator, 3x}<BR>\n" );
document.write( "3x(5/3x) + 3x(3/x) = 3x(1) {multiplied each term by 3x}<BR>\n" );
document.write( "5 + 9 = 3x {cancelled and multiplied what's left}<BR>\n" );
document.write( "3x = 14 {added 5 and 9}<BR>\n" );
document.write( "x = 14/3 {divided both sides by 3}<BR>\n" );
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