document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48081>Question 48081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This problem comes from the Accuplacer practice test.\r<BR>\n" );
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document.write( "Sarah needs to make a cake and some cookies. The cake requires 3/8 cup of sugar and the cookies require 3/5 cup of sugar. Sarah has 15/16 cups of sugar. Does she have enough sugar, or how much more does she need?  <BR>\n" );
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document.write( "  She has enough sugar. <BR>\n" );
document.write( "  She needs 1/8 of a cup of sugar. <BR>\n" );
document.write( "  She needs 3/80 of a cup of sugar. <BR>\n" );
document.write( "  She needs 4/19 of a cup of sugar. <BR>\n" );
document.write( "  She needs 1/9 of a cup of sugar. \r<BR>\n" );
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document.write( "I can get as far as: 3/8 + 3/5 -> 15/40 + 24/40 = 39/40.  I know the answer is 3/80C. of Sugar, but I can't figure out how they worked it out.  I've tried several variations, but cannot = 3/80. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31816 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/8 cup of sugar and the cookies require 3/5 cup of sugar. Sarah has 15/16 cups of sugar.\r<BR>\n" );
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document.write( "3/8 +3/5 = (15+24)/40= 39/40\r<BR>\n" );
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document.write( "15/16R39/40\r<BR>\n" );
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document.write( "Which is greater? 15/16 or 39/40<BR>\n" );
document.write( "Crossmultiply to get:<BR>\n" );
document.write( "15*39R16*40<BR>\n" );
document.write( "585R640<BR>\n" );
document.write( "As you see 585<640<BR>\n" );
document.write( "Therefore 15/16 is less that 39/40<BR>\n" );
document.write( "Sarah does not have enough sugar.\r<BR>\n" );
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document.write( "How much more does she need?<BR>\n" );
document.write( "39/40-15/16<BR>\n" );
document.write( "=78/80- 75/80<BR>\n" );
document.write( "= 3/80 of a cup of sugar\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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