document.write( "Question 464186: Bottle 1 has 14 liters of 10% acid and we need to add some of bottle 2 which is 60% acid to form a new bottle which is 25% ALCOHOL. PART 1- WHAT IS THE VOLUME THAT WE NEED FROM BOTTLE 2? Part 2- WHAT IS THE VOLUME OF THE NEW BOTTLE?? \n" ); document.write( "
Algebra.Com's Answer #318154 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Bottle 1 has 14 liters of 10% acid and we need to add some of bottle 2 which is \n" ); document.write( " 60% acid to form a new bottle which is 25% ALCOHOL. \n" ); document.write( " PART 1- WHAT IS THE VOLUME THAT WE NEED FROM BOTTLE 2? \n" ); document.write( ": \n" ); document.write( "Let x = vol from bottle 2 required \n" ); document.write( "Write the decimal equiv mixture equation: \n" ); document.write( ".10(14) + .60x = .25(x+14) \n" ); document.write( "1.4 + .60x = .25x + 3.5 \n" ); document.write( ".60x - .25x = 3.5 - 1.4 \n" ); document.write( ".35x = 2.1 \n" ); document.write( "x = \n" ); document.write( "x = 6 liters of 60% acid required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Part 2- WHAT IS THE VOLUME OF THE NEW BOTTLE?? \n" ); document.write( "14 + 6 = 20 liters \n" ); document.write( " |