document.write( "Question 464392: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work. .
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Algebra.Com's Answer #318121 by nerdybill(7384)\"\" \"About 
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Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work. .
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\n" ); document.write( "Determine slope of:
\n" ); document.write( "10x – 6y = -11
\n" ); document.write( "By rearranging into \"slope-intercept\" form:
\n" ); document.write( "10x – 6y = -11
\n" ); document.write( "10x = 6y -11
\n" ); document.write( "10x + 11 = 6y
\n" ); document.write( "(10/6)x + 11/6 = y
\n" ); document.write( "(5/3)x + 11/6 = y
\n" ); document.write( "slope is 5/3
\n" ); document.write( "a line perpendicular must have a \"negative reciprocal\":
\n" ); document.write( "(5/3)m = -1
\n" ); document.write( "m = -3/5 (slope of new line)
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\n" ); document.write( "using the slope (-3/5) and (-5, -8) plug into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - (-8) = (-3/5)(x - (-5))
\n" ); document.write( "y + 8 = (-3/5)(x + 5)
\n" ); document.write( "y + 8 = (-3/5)x - 3
\n" ); document.write( "y = (-3/5)x - 11 (this is what they're looking for)\r
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