document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426148>Question 426148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much alloy that is 40% copper should be mixed with 300 ounces of an alloy that is 70% copper in order to get an alloy that is 50% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318090 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .4m+300(.7)=.5(m+300)<BR>\n" );
document.write( ".4m+210=.5m+150<BR>\n" );
document.write( ".1m=60<BR>\n" );
document.write( "m=60/.1=600<BR>\n" );
document.write( "You need 600 ozs. for your mix.. </SPAN>\n" );
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