document.write( "Question 464266: Can you show me the STEPS to solve the following: 1 over x-1 + 4 over x^2-1 - 2 over x^2-2x+1. Thanks. \n" ); document.write( "
Algebra.Com's Answer #318041 by Gogonati(855)\"\" \"About 
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To solve the equation \"1%2F%28x-1%29%2B4%2F%28x%5E2-1%29=%28-2%29%2F%28x%5E2-2x%2B1%29\", first we factor the \r
\n" ); document.write( "\n" ); document.write( "denominators to find the LCD.\"1%2F%28x-1%29%2B4%2F%28x-1%29%28x%2B1%29=%28-2%29%2F%28x-1%29%5E2\". the LCD is\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2%28x%2B1%29\". Second write all terms with the same denominator:\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by LCD, and cancel like terms:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-1%2B4%28x-1%29=-2%28x%2B1%29\", set the equation equal to zero:\"x%5E2-2x-3=0\"\r
\n" ); document.write( "\n" ); document.write( "Solve this equation by factoring:\"%28x%2B1%29%28x-3%29=0\" The solution is:\r
\n" ); document.write( "\n" ); document.write( "x+1=0 <=> x=-1, and x-3=0 <=> x=3. Reject the solution x=-1 because the equation is undefined and the only solution is x=3.
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