document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464287>Question 464287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a+b=180 ,a-2b=30 , then find the value of a and b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318036 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a + b = 180 ------> -a - b = -180 {multiplied top equation by -1}<BR>\n" );
document.write( "a - 2b = 30\r<BR>\n" );
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document.write( "-a - b = -180 {new top equation}<BR>\n" );
document.write( "a - 2b = 30 {original bottom equation}<BR>\n" );
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document.write( "-3b = -150 {added the two equations together}<BR>\n" );
document.write( "b = 50 {divided both sides by -3}\r<BR>\n" );
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document.write( "a + b = 180 {original top equation}<BR>\n" );
document.write( "a + 50 = 180 {substituted 50, in for b, into top equation}<BR>\n" );
document.write( "a = 130 {subtracted 50 from both sides}\r<BR>\n" );
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document.write( "a = 130 and b = 50<BR>\n" );
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