document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063>Question 1063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"where would you expect the vertex on the graph of  y = (x - 4)^2 + 5 to be?\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #318 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, look at the general vertex form of parabola<BR>\n" );
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document.write( "y = (x-h)^2+k<BR>\n" );
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document.write( "where h is the location of the point on x-axis and k is the location of the point of the y-axis. So in your equation, y = (x-4)^2+5, the vertex is gonna be (4,5). Let me show u the graph...<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28200%2C400%2C-20%2C20%2C-100%2C100%2C%28x-4%29%5E2%2B5%29 ALIGN=MIDDLE  ALT=\"graph%28200%2C400%2C-20%2C20%2C-100%2C100%2C%28x-4%29%5E2%2B5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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