document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464229>Question 464229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles. Two angles are supplementary.If one angle measures 45° less than twice the measure of its supplement, find the measure of each angle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317999 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Supplementary angles. Two angles are supplementary.If one angle measures 45° less than twice the measure of its supplement, find the measure of each angle.\"\r<BR>\n" );
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document.write( "Supplementary angles add up to 180°.\r<BR>\n" );
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document.write( "x = one angle<BR>\n" );
document.write( "180 - x = its supplement {supplementary angles add up to 180}\r<BR>\n" );
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document.write( "x = 2(180 - x) - 45 {one angle is 45 less than twice its supplement}<BR>\n" );
document.write( "x = 360 - 2x - 45 {used distributive property}<BR>\n" );
document.write( "x = -2x + 315 {combined like terms on right}<BR>\n" );
document.write( "3x = 315 {added 2x to both sides}<BR>\n" );
document.write( "x = 105 {divided both sides by 3}<BR>\n" );
document.write( "180 - x = 75 {substituted 105, in for x, into 180 - x}\r<BR>\n" );
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document.write( "105° and 75° are the two angles<BR>\n" );
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