document.write( "Question 48064: \"solve the following trigonometric eqaution for the given domain (cont.)\":
\n" ); document.write( "can someone show me how to solve the below eqautions and explain them to me? thanks.
\n" ); document.write( "i dont understand what you have to do with the \"x\" and a lot of other things. please help thank you.\r
\n" ); document.write( "\n" ); document.write( "a.) sin 3x = \"sqrt%283%29%2F2\" ....for all x
\n" ); document.write( "b.) tan 2x= 0 ....on [\"pi%2F2\",\"3pi%2F2\"]
\n" ); document.write( "c.) sec\"pi\"x= 2......for all x
\n" ); document.write( "d.) sin^2 x + sin x=0....on [0,2\"pi\"]
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Algebra.Com's Answer #31797 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a.) sin 3x = (sqrt3)/2 ....for all x\r
\n" ); document.write( "\n" ); document.write( "The reference angle that has this sin value is pi/3
\n" ); document.write( "The sin is positive in the 1st and 2nd Quadrants.
\n" ); document.write( "So, looking at all x, 3x= pi/3+2npi or 3x=(2/3)x+2npi
\n" ); document.write( "Then x=pi/9 + (2/3)npi or x= (pi/9)x+(2/3)npi
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\n" ); document.write( "tan 2x= 0 ....on [pi/2,3pi/2]
\n" ); document.write( "The reference angle whose tan value is 0 is 0 and pi
\n" ); document.write( "So, looking at the given interval 2x=pi and x=pi/2
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\n" ); document.write( "c.) secx= 2......for all x
\n" ); document.write( "The reference angle for sec value of 2 is pi/3
\n" ); document.write( "The sec is positive in the 1st and 4th quadrants.
\n" ); document.write( "so, looking at all x, x=pi/3 + 2npi or x=(5/3)pi + 2npi
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\n" ); document.write( "d.) sin^2 x + sin x=0....on [0,2pi]
\n" ); document.write( "sinx(sinx+1)=0
\n" ); document.write( "sinx=0 or sinx=-1
\n" ); document.write( "sinx=0 on the interval when x=0, or x=pi, or x=2pi
\n" ); document.write( "sinx=-1 on the interval when x=(3/2)pi
\n" ); document.write( "------------------------------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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