document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=464058>Question 464058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 100kg Brick On The Moon. If The Moon Had 5x Less Gravity Than Earth, What Would The Weight Of The Brick Now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317901 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Technically, the kilogram is a unit of mass (not weight, the two are different), so the mass of the brick on Earth is 100 kg and the weight of the brick on Earth would be\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (100 kg)(9.81 \frac{m}{s^2}) = 981 N\"> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );