document.write( "Question 464104: how do I find the volume of a rectangular solid with cylindrical hole of diameter 34? I believe the l=19, w=59, h=56 \n" ); document.write( "
Algebra.Com's Answer #317889 by Theo(13342)\"\" \"About 
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your rectangular solid measures:
\n" ); document.write( "19 length
\n" ); document.write( "59 width
\n" ); document.write( "56 height\r
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\n" ); document.write( "\n" ); document.write( "the cylinder that will be removed from your rectangular solid has a diameter of 34.\r
\n" ); document.write( "\n" ); document.write( "that means it has a radius of 34/2 = 17.\r
\n" ); document.write( "\n" ); document.write( "you need to get the volume of the rectangular solid and subtract the volume of the cylinder.\r
\n" ); document.write( "\n" ); document.write( "the volume of the rectangular solid is equal to 19 * 59 * 56 = 62776 cubic units.\r
\n" ); document.write( "\n" ); document.write( "that's what it would be without the removal of the cylindrical solid.\r
\n" ); document.write( "\n" ); document.write( "the volume of your cylinder is equal to pi * radius squared * height.\r
\n" ); document.write( "\n" ); document.write( "that would be equal to pi * 17 squared * 56 which is equal to 50843.53551 cubic units.\r
\n" ); document.write( "\n" ); document.write( "The volume of the rectangular solid that is left after removing the cylindrical solid that will leave a cylindricall hole is equal to 62776 - 50843.53551 = 11932.46449 cubic units which can be rounded to whatever accuracy desired.\r
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