document.write( "Question 464052: How many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #317857 by jorel1380(3719)\"\" \"About 
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m(.70)+80(.25)=.6(m+80)
\n" ); document.write( ".7m+20=.6m+48
\n" ); document.write( ".1m=28
\n" ); document.write( "m=28/.1=280 gallons of 25% antifreeze needed..
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