document.write( "Question 464009: The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car travelling 30 mph can stop in 50 ft, how many feet will it take the same car to stop when it is travelling 20 mph? \n" ); document.write( "
Algebra.Com's Answer #317837 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. \n" ); document.write( "--- \n" ); document.write( "d = kr^2 \n" ); document.write( "--- \n" ); document.write( "Solve for \"k\" using \"a car travelling 30 mph can stop in 50 ft\" \n" ); document.write( "50 = k*30^2 \n" ); document.write( "k = 50/900 \n" ); document.write( "k = 0.0556 \n" ); document.write( "--------------- \n" ); document.write( "Equation: \n" ); document.write( "d = 0.0556*r^2 \n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "How many feet will it take the same car to stop when it is travelling 20 mph? \n" ); document.write( "d = 0.0556*20^2 \n" ); document.write( "--- \n" ); document.write( "distance = 22.22 ft \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================== \n" ); document.write( " |