document.write( "Question 464002: Write an equation of the line then graph the line with a slope of -5 and y-intercept (0,3).
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document.write( "The equation I came up with is y=-5x+3. Is this correct?\r
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document.write( "Graph:
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document.write( "I know where to plot the y-intercept of (0,3) but not sure how to graph the slope of -5. Would it be -5/1 (Rise/Run) and if so, would it be 5 down and 1 to the right? \n" );
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Algebra.Com's Answer #317819 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! slope = -5 {or -5/1 in terms of rise over run} \n" ); document.write( "y-intercept = 3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Slope-intercept form is y = mx + b \n" ); document.write( "m is the slope {rise over run} \n" ); document.write( "b is the y-intercept {where the line crosses the y-axis}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = -5x + 3 is the equation of the line\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To graph: \n" ); document.write( "- put a point on 3, on the y-axis \n" ); document.write( "- from there, since the slope is -5/1, go down 5 and to the right 1 and put another point \n" ); document.write( "- draw a line through the two points \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |