document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463945>Question 463945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the sides of an equilateral triangle are 10 cm what is the length of the altitude ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317795 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sides of an equilateral triangle are 10 cm.<BR>\n" );
document.write( "what is the length of the altitude?<BR>\n" );
document.write( "drop an altitude from one of the angles to the opposite side.<BR>\n" );
document.write( "that altitude will be perpendicular to the opposite side and will cut the opposite side exactly in half to form 2 right triangles.<BR>\n" );
document.write( "each of those right triangles will have a hypotenuse of 10 cm and a base let of 5 cm.<BR>\n" );
document.write( "use the pythagorean formula to find the other leg.<BR>\n" );
document.write( "that leg will be the altitude.<BR>\n" );
document.write( "call that leg x.<BR>\n" );
document.write( "you get x^2 + 5^2 = 10^2 which becomes x^2 + 25 = 100 which becomes x^2 = 75 which becomes x = sqrt(75).<BR>\n" );
document.write( "that's the length of your altitude.<BR>\n" );
document.write( "you can simplify that to make it 5*sqrt(3).\r<BR>\n" );
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