document.write( "Question 463898: This is a problem from my summer homework that should be really easy, but I'm completely blanking out on how to solve it!\r
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document.write( "\"Christy drove at 50 miles per hour for h hours but arrived g hours late. How fast should Christy have driven to have arrived on time?\"\r
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document.write( "I started some of my own work, but I really had no idea what I was doing, so it was rather pointless, but thanks to anyone who can help! \n" );
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Algebra.Com's Answer #317756 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "distance = 50 * h = 50h, time = h but g hours late.\r \n" ); document.write( "\n" ); document.write( "actual time require = (h-g) hours\r \n" ); document.write( "\n" ); document.write( "require speed = 50h/(h-g)\r \n" ); document.write( "\n" ); document.write( "difference between speed = 50h/(h-g) - 50 = 50g/(h-g) miles/hour\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |