document.write( "Question 48025: dear tutors, plz help me find the value of a and b so that x/a + y/b =1 passes through (3,-2) and (9,2).
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document.write( " I've already tried answering it but i dont know how..
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document.write( "i solved the value of x and y.. \n" );
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Algebra.Com's Answer #31770 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3,-2) --> \n" ); document.write( "--> now multiply all terms by ab \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(9,2) --> \n" ); document.write( "--> now multiply all terms by ab, again \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have \n" ); document.write( "3b - 2a = ab and \n" ); document.write( "9b + 2a = ab\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lets add them: \n" ); document.write( "12b = 2ab \n" ); document.write( "2a = 12 \n" ); document.write( "--> a = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, \n" ); document.write( "3b = -12 \n" ); document.write( "b = -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK: use (3,-2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "is 1... correct\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CHECK: use (9,2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "is 1... correct\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon \n" ); document.write( " \n" ); document.write( " |