document.write( "Question 458540: 2cosx= sin2x btween 0 and 3 pie \n" ); document.write( "
Algebra.Com's Answer #317697 by lwsshak3(11628)\"\" \"About 
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2cosx= sin2x btween 0 and 3 pie
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\n" ); document.write( "2cosx= sin2x
\n" ); document.write( "2cosx= 2sinxcosx
\n" ); document.write( "sinx=1
\n" ); document.write( "x=π/2,5π/2
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