document.write( "Question 463692: log(2-x)=.05
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Algebra.Com's Answer #317679 by nerdybill(7384)\"\" \"About 
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log(2-x)=.05
\n" ); document.write( "(2-x)= 10^(.05)
\n" ); document.write( "2-x= 1.122
\n" ); document.write( "-x= 1.122-2
\n" ); document.write( "-x= -0.878
\n" ); document.write( "x= 0.878\r
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