document.write( "Question 463692: log(2-x)=.05
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document.write( "Find X \n" );
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Algebra.Com's Answer #317679 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! log(2-x)=.05 \n" ); document.write( "(2-x)= 10^(.05) \n" ); document.write( "2-x= 1.122 \n" ); document.write( "-x= 1.122-2 \n" ); document.write( "-x= -0.878 \n" ); document.write( "x= 0.878\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |