document.write( "Question 463712: the preimeter of a rectangle is 43in. more than the length. the width is 10in. find the length of the rectangle \n" ); document.write( "
Algebra.Com's Answer #317672 by algebrahouse.com(1659)\"\" \"About 
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\"the preimeter of a rectangle is 43in. more than the length. the width is 10in. find the length of the rectangle\"\r
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\n" ); document.write( "\n" ); document.write( "x = length
\n" ); document.write( "10 = width
\n" ); document.write( "x + 43 = perimeter {perimeter is 43 more than the length}\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = 2(length) + 2(width)\r
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\n" ); document.write( "\n" ); document.write( "x + 43 = 2x + 2(10) {substituted into formula for perimeter}
\n" ); document.write( "x + 43 = 2x + 20 {multiplied 2 by 10}
\n" ); document.write( "43 = x + 20 {subtracted x from both sides}
\n" ); document.write( "x = 23 {subtracted 20 from both sides}\r
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\n" ); document.write( "\n" ); document.write( "23 in. is the length
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