document.write( "Question 463648: Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method.
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document.write( "•Multiply the equation 2x + y = 10 by -2; -4x - 2y = -10.
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document.write( "•Add the equation 4x + 4y = 16 and the equation -4x - 2y = -10 together; 2y = 6.
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document.write( "•Isolate the variable y by dividing both sides of the equation by 2; y = 3.
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document.write( "Can anyone tell us why I multiplied the equation 2x + y = 10 by -2?
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document.write( "is this correct so far? please help!! \n" );
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Algebra.Com's Answer #317626 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Let me try to solve your system of equation 4x + 4y = 16 and 2x + y = 10 using the elimination method. \n" ); document.write( "•Multiply the equation 2x + y = 10 by -2; -4x - 2y = -10. \n" ); document.write( "•Add the equation \n" ); document.write( "4x + 4y = 16 and the equation \n" ); document.write( "-4x - 2y = -10 together; \n" ); document.write( "----------------- \n" ); document.write( "2y = 6. \n" ); document.write( "•Isolate the variable y by dividing both sides of the equation by 2; y = 3. \n" ); document.write( "Can anyone tell us why I multiplied the equation 2x + y = 10 by -2? \n" ); document.write( "To get the coefficients of x to match. \n" ); document.write( "-------------- \n" ); document.write( "is this correct so far? please help!! \n" ); document.write( "It's correct, y = 3 \n" ); document.write( "------------- \n" ); document.write( "Sub for y in 2x + y = 10 \n" ); document.write( "2x + 3 = 10 \n" ); document.write( "2x = 7 \n" ); document.write( "x = 3.5 or 7/2 \n" ); document.write( "That's all \n" ); document.write( " \n" ); document.write( " |