document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463626>Question 463626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat can go 66 miles downstream and 54 miles upstream in the same amount of time. Find the rate of the boat in still water if the current is moving 2 mph. rate of boat=r rate of current =x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317604 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance divided by rate equals time. Going down stream the rate is r+2 so for going down stream the time is\r<BR>\n" );
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document.write( "66/(r+2)<BR>\n" );
document.write( "For going up stream the rate is r-2 so the time for going up stream is<BR>\n" );
document.write( "54/(r-2)\r<BR>\n" );
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document.write( "The times are equal so<BR>\n" );
document.write( "66/(r+2) = 59/(r-2)<BR>\n" );
document.write( "Multiply this equation by (r+2)(r-2)\r<BR>\n" );
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document.write( "(r+2)(r-2)(66/(r+2)) = (r+2)(r-2)(59/(r-2))<BR>\n" );
document.write( "(r-2)66 = (r+2)59<BR>\n" );
document.write( "66r - 132 = 59r - 118<BR>\n" );
document.write( "66r - 59r = 132 - 118<BR>\n" );
document.write( "7r = 14<BR>\n" );
document.write( "r = 14/7<BR>\n" );
document.write( "r = 2 </SPAN>\n" );
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