document.write( "Question 463552: find the two consecutive odd integers such that the lesser is added to twice the greater, the result is 24 more than the greater interger \n" ); document.write( "
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\"find the two consecutive odd integers such that the lesser is added to twice the greater, the result is 24 more than the greater interger\"\r
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\n" ); document.write( "\n" ); document.write( "x = 1st odd integer
\n" ); document.write( "x + 2 = 2nd odd integer {odd integers increase by 2 each time}\r
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\n" ); document.write( "\n" ); document.write( "x + 2(x + 2) = x + 2 + 24 {the lesser is added to twice greater, result is 24 more than greater}
\n" ); document.write( "x + 2x + 4 = x + 26 {used distributive property on left, combined like terms on right}
\n" ); document.write( "3x + 4 = x + 26 {combined like terms on left}
\n" ); document.write( "3x = x + 22 {subtracted 4 from both sides}
\n" ); document.write( "2x = 22 {subtracted x from both sides}
\n" ); document.write( "x = 11 {divided both sides by 2}
\n" ); document.write( "x + 2 = 13 {substituted 11, in for x, into x + 2}\r
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\n" ); document.write( "\n" ); document.write( "11 and 13 are the two odd integers\r
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\n" ); document.write( "\n" ); document.write( "For more help like this, ask the house: www.algebrahouse.com\r
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