document.write( "Question 47981: Can you show me how to factor 8x^3-1 \n" ); document.write( "
Algebra.Com's Answer #31756 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor:
\n" ); document.write( "\"8x%5E3-1\" You should recognise this as the difference of two cubes \"%282x%29%5E3-%281%29%5E3\"
\n" ); document.write( "The difference of two cubes can be factored thus:
\n" ); document.write( "\"A%5E3-B%5E3+=+%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\" Applying this to your problem in which A = 2x and B = 1:
\n" ); document.write( "\"%282x%29%5E3-%281%29%5E3+=+%282x-1%29%284x%5E2%2B2x%2B1%29\"...and this is as far as you can go with this.
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