document.write( "Question 463491: A rectangle is 9 cm longer than it is wide. The width is one seventh of the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #317554 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! A rectangle is 9 cm longer than it is wide. The width is one seventh of the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "======================================================== \n" ); document.write( "Let l = the length of the rectangle \n" ); document.write( "Let w = the width of the rectangle \n" ); document.write( "The length is 9 cm more than the width. In equation form this is: \n" ); document.write( "l = w + 9 [1] \n" ); document.write( "The width is 1/7 of the perimeter. Since the perimeter = 2l + 2w, we can write: \n" ); document.write( "w = 1/7(2l + 2w) = 2/7(l + w) [2] \n" ); document.write( "Substitute the value for l in [1] into [2]: \n" ); document.write( "w = 2/7(w + 9 + w) \n" ); document.write( "Solve for w: \n" ); document.write( "w = 4/7w + 18/7 \n" ); document.write( "3/7w = 18/7 \n" ); document.write( "w = 6 \n" ); document.write( "Therefore the length, l = 6 + 9 = 15 \n" ); document.write( "Ans: w=6, l=15 \n" ); document.write( " \n" ); document.write( " |