document.write( "Question 463491: A rectangle is 9 cm longer than it is wide. The width is one seventh of the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #317554 by htmentor(1343)\"\" \"About 
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A rectangle is 9 cm longer than it is wide. The width is one seventh of the perimeter. What are the dimensions of the rectangle?
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\n" ); document.write( "Let l = the length of the rectangle
\n" ); document.write( "Let w = the width of the rectangle
\n" ); document.write( "The length is 9 cm more than the width. In equation form this is:
\n" ); document.write( "l = w + 9 [1]
\n" ); document.write( "The width is 1/7 of the perimeter. Since the perimeter = 2l + 2w, we can write:
\n" ); document.write( "w = 1/7(2l + 2w) = 2/7(l + w) [2]
\n" ); document.write( "Substitute the value for l in [1] into [2]:
\n" ); document.write( "w = 2/7(w + 9 + w)
\n" ); document.write( "Solve for w:
\n" ); document.write( "w = 4/7w + 18/7
\n" ); document.write( "3/7w = 18/7
\n" ); document.write( "w = 6
\n" ); document.write( "Therefore the length, l = 6 + 9 = 15
\n" ); document.write( "Ans: w=6, l=15
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