document.write( "Question 463455: seven years ago, Mary was 6 times as old as Cora. in one year, she will be only twice as old as Cora. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #317536 by amoresroy(361)![]() ![]() You can put this solution on YOUR website! Let M = age of Mary \n" ); document.write( " C = age of Cora\r \n" ); document.write( "\n" ); document.write( "1st equation: \n" ); document.write( "M-7 = 6(C-7) \n" ); document.write( "M-7 = 6C-42 \n" ); document.write( "2nd equation: \n" ); document.write( "M+1 = 2(C+1) \n" ); document.write( "M+1 = 2C+2\r \n" ); document.write( "\n" ); document.write( "Subtract the 1st equation by 2nd equation to eliminate M \n" ); document.write( "-7-1 = 6C-42-2c-2 \n" ); document.write( "-8+44 = 4C \n" ); document.write( "4C = 36 \n" ); document.write( "C = 9\r \n" ); document.write( "\n" ); document.write( "Substitute C = 9 in 2nd equation to get \n" ); document.write( "M+1 = 2*9 +2 \n" ); document.write( "M = 19\r \n" ); document.write( "\n" ); document.write( "Mary is 19 years old. \n" ); document.write( "Cora is 9 years old. \n" ); document.write( " |