document.write( "Question 463455: seven years ago, Mary was 6 times as old as Cora. in one year, she will be only twice as old as Cora. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #317536 by amoresroy(361)\"\" \"About 
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Let M = age of Mary
\n" ); document.write( " C = age of Cora\r
\n" ); document.write( "\n" ); document.write( "1st equation:
\n" ); document.write( "M-7 = 6(C-7)
\n" ); document.write( "M-7 = 6C-42
\n" ); document.write( "2nd equation:
\n" ); document.write( "M+1 = 2(C+1)
\n" ); document.write( "M+1 = 2C+2\r
\n" ); document.write( "\n" ); document.write( "Subtract the 1st equation by 2nd equation to eliminate M
\n" ); document.write( "-7-1 = 6C-42-2c-2
\n" ); document.write( "-8+44 = 4C
\n" ); document.write( "4C = 36
\n" ); document.write( "C = 9\r
\n" ); document.write( "\n" ); document.write( "Substitute C = 9 in 2nd equation to get
\n" ); document.write( "M+1 = 2*9 +2
\n" ); document.write( "M = 19\r
\n" ); document.write( "\n" ); document.write( "Mary is 19 years old.
\n" ); document.write( "Cora is 9 years old.
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