document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463441>Question 463441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve 100to 2x+3 power to equal 1000 to the x+5 solve for x?<BR>\n" );
document.write( "How do you solve for x 4to the 5x+1=16 to 2x-1?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317531 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve 100to 2x+3 power to equal 1000 to the x+5 solve for x?<BR>\n" );
document.write( "How do you solve for x 4to the 5x+1=16 to 2x-1? <BR>\n" );
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document.write( "100^(2x+3) = 1000^(x+5)<BR>\n" );
document.write( "Taking the log (base 10) of both sides gives:<BR>\n" );
document.write( "(2x+3)log(100) = (x+5)log(000)<BR>\n" );
document.write( "(2x+3)2 = (x+5)3<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "4x+6 = 3x+15<BR>\n" );
document.write( "This gives x = 9<BR>\n" );
document.write( "The 2nd problem is solved the same way, but use log base 4<BR>\n" );
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