document.write( "Question 463435: Please answer as soon as possible...\r
\n" ); document.write( "\n" ); document.write( "1) 3 graduating students who are applying for a part-time job have ages which sum up to 60. The sum of the ages of the first 2 students less the age of the third student gives 12. If the third student is 5 yrs. older than the first student, find their ages.
\n" ); document.write( "

Algebra.Com's Answer #317522 by alicealc(293)\"\" \"About 
You can put this solution on YOUR website!
1st student's age = a
\n" ); document.write( "2nd student's age = b
\n" ); document.write( "3rd student's age = c\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a + b + c = 60
\n" ); document.write( "a + b - c = 12
\n" ); document.write( "c = 5 + a\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a + b + c = 60
\n" ); document.write( "a + b - c = 12
\n" ); document.write( "--------------- (-)
\n" ); document.write( "2c = 48
\n" ); document.write( "c = 48/2 = 24\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "c = 5 + a
\n" ); document.write( "24 = 5 + a
\n" ); document.write( "a = 24 - 5 = 19\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a + b + c = 60
\n" ); document.write( "19 + b + 24 = 60
\n" ); document.write( "43 + b = 60
\n" ); document.write( "b = 60 - 43 = 17\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( "1st student's age = 19
\n" ); document.write( "2nd student's age = 17
\n" ); document.write( "3rd student's age = 24
\n" ); document.write( "
\n" ); document.write( "
\n" );