document.write( "Question 463435: Please answer as soon as possible...\r
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document.write( "1) 3 graduating students who are applying for a part-time job have ages which sum up to 60. The sum of the ages of the first 2 students less the age of the third student gives 12. If the third student is 5 yrs. older than the first student, find their ages. \n" );
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Algebra.Com's Answer #317522 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! 1st student's age = a \n" ); document.write( "2nd student's age = b \n" ); document.write( "3rd student's age = c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a + b + c = 60 \n" ); document.write( "a + b - c = 12 \n" ); document.write( "c = 5 + a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a + b + c = 60 \n" ); document.write( "a + b - c = 12 \n" ); document.write( "--------------- (-) \n" ); document.write( "2c = 48 \n" ); document.write( "c = 48/2 = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c = 5 + a \n" ); document.write( "24 = 5 + a \n" ); document.write( "a = 24 - 5 = 19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a + b + c = 60 \n" ); document.write( "19 + b + 24 = 60 \n" ); document.write( "43 + b = 60 \n" ); document.write( "b = 60 - 43 = 17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( "1st student's age = 19 \n" ); document.write( "2nd student's age = 17 \n" ); document.write( "3rd student's age = 24 \n" ); document.write( " \n" ); document.write( " |