document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463366>Question 463366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4x-y=3<BR>\n" );
document.write( "3x+y=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317500 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x - y = 3<BR>\n" );
document.write( "3x + y = 4<BR>\n" );
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document.write( "7x = 7 {added the two equations together}<BR>\n" );
document.write( "x = 1 {divided both sides by 7}\r<BR>\n" );
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document.write( "3x + y = 4 {bottom original equation}<BR>\n" );
document.write( "3(1) + y = 4 {substituted 1, in for x, into bottom original equation}<BR>\n" );
document.write( "3 + y = 4 {multiplied 3 by 1}<BR>\n" );
document.write( "y = 1 {subtracted 3 from both sides}\r<BR>\n" );
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document.write( "x = 1 and y = 1<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br><br> </SPAN>\n" );
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