document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435942>Question 435942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 150 milliliters of a 43% solution but has only 13% and<BR>\n" );
document.write( "58% solutions available. Find how many milliliters of each that should be<BR>\n" );
document.write( "mixed to get the desired solution.\r<BR>\n" );
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document.write( "Can you show me how you formulated.. this is what I have so far.\r<BR>\n" );
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document.write( "43(150) = 13x + 58y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317486 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 150x.43=64.5 mL<BR>\n" );
document.write( "p+q=150<BR>\n" );
document.write( ".13p+.58q=64.5<BR>\n" );
document.write( "13p+58q=6450<BR>\n" );
document.write( "13p+13q=1950<BR>\n" );
document.write( "45q=4500<BR>\n" );
document.write( "q=100<BR>\n" );
document.write( "p=50<BR>\n" );
document.write( "The chemist needs 50 mL of 13% solution and 100 mL of 58% solution.. </SPAN>\n" );
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