document.write( "Question 435362: Pure acid is to be added to a 5% acid solution to obtain 95L of 44% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? \n" ); document.write( "
Algebra.Com's Answer #317481 by jorel1380(3719)\"\" \"About 
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95x.44=41.8
\n" ); document.write( "m+n=95
\n" ); document.write( "m+.05n=41.8
\n" ); document.write( "100m+5n=4180
\n" ); document.write( "100m+100n=9500
\n" ); document.write( "95n=5320
\n" ); document.write( "n=56
\n" ); document.write( "m=39
\n" ); document.write( "You need 39 liters of pure acid and 56 liters of 5% acid for your mix..
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