document.write( "Question 435362: Pure acid is to be added to a 5% acid solution to obtain 95L of 44% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? \n" ); document.write( "
Algebra.Com's Answer #317481 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 95x.44=41.8 \n" ); document.write( "m+n=95 \n" ); document.write( "m+.05n=41.8 \n" ); document.write( "100m+5n=4180 \n" ); document.write( "100m+100n=9500 \n" ); document.write( "95n=5320 \n" ); document.write( "n=56 \n" ); document.write( "m=39 \n" ); document.write( "You need 39 liters of pure acid and 56 liters of 5% acid for your mix.. \n" ); document.write( " |