document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463083>Question 463083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To a sugar solution of 3 liters containing 40% sugar one liter of water is added. The percentage of sugar in the new solution is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317348 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sugar = 40/100 * 3 = 120/100 = 1.2 liters<BR>\n" );
document.write( "percentage of new sugar <BR>\n" );
document.write( "= 1.2/(3+1) * 100%<BR>\n" );
document.write( "= 1.2/4 * 100%<BR>\n" );
document.write( "= 0.3 * 100%<BR>\n" );
document.write( "= 30% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );