document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463106>Question 463106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 318 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317340 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = l<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+2%2Aw ALIGN=MIDDLE  ALT=\"l+=+2%2Aw\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "perimeter = 318<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Al+%2B+2%2Aw+=+318 ALIGN=MIDDLE  ALT=\"2%2Al+%2B+2%2Aw+=+318\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide all by 2:<BR>\n" );
document.write( "l + w = 159<BR>\n" );
document.write( "2w + w = 159<BR>\n" );
document.write( "3w = 159<BR>\n" );
document.write( "w = 159/3 <BR>\n" );
document.write( "w = 53<BR>\n" );
document.write( "l = 2w = 2 * 53 = 106\r<BR>\n" );
document.write( "\n" );
document.write( "so, the dimension will be: 106 feet long and 53 feet wide </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );