document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=463024>Question 463024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system by substitution \r<BR>\n" );
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document.write( "3x - 3y = -6<BR>\n" );
document.write( "x + 2y = -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317324 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the bottom equation, x = -2y - 1.\r<BR>\n" );
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document.write( "Putting this into the top equation, we get 3(-2y - 1) - 3y = -6, or\r<BR>\n" );
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document.write( "-6y - 3 - 3y = -6, \r<BR>\n" );
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document.write( "-9y = -3, or y = 1/3.\r<BR>\n" );
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document.write( "==> x = -2/3 - 1 = -5/3. </SPAN>\n" );
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